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Question

Geometrical isomerism is exhibited by:


A
2-chlorobut-2-ene
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B
but-2-ene
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C
3-methylpent-2-ene
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D
2-methyl but-2-ene
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Solution

The correct options are
A 2-chlorobut-2-ene
B but-2-ene
C 3-methylpent-2-ene
The main conditions for exhibiting geometrical isomerism are 
(i) the presence of a double bond. 
(ii) presence of different groups on double-bonded C-atom. 
(iii) presence of at least one similar group on adjacent double-bonded carbon atoms.

$$2-chlorobut-2-ene, but-2-ene, 3-methylpent-2-ene$$  show geometrical isomerism. but $$2-methyl \ but-2-ene$$ does not show geometrical isomerism because $$\text{the same(−CH3) group}$$ is present on double-bonded carbon).


Chemistry

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