Geometrical isomerism is not shown by:

C H_{3} - C H_{2} - C (C H_{3}) = C (C H_{3}) C H_{2} - C H_{3}

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C_{2} H_{5} - C H = C H - C H_{2} I

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C H_{2} = C (C l) C H_{3}

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C H_{3} - C H = C H - C H = C H_{2}

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Solution

The correct option is B $C H_{2} = C (C l) C H_{3}$
Geometrical isomerism is not shown by $C H_{2} = C (C l) C H_{3}$ as two identical atoms (H atoms) are attached to unsaturated carbon atom.

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Similar questions

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

H_{3} C - C H_{2} - C H_{3} | C = C H - C | H C_{2} H_{5} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{3}

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

I U P A C

C H_{3} - C H = C H - C H_{2} - C H = C H - C H - C H_{2} - C H = C H_{2}

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C_{2} H_{5}

A g N O_{3}

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