Give balanced equations to obtain ' $C O_{2}$ ':

{C a C O}_{3} + 4 H C l \to {C a C l}_{2} + 2 H_{2} O + {C O}_{2}

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{C a C O}_{3} + 2 H C l \to {C a C l}_{2} + H_{2} O + {C O}_{2}

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2 {C a C O}_{3} + 2 H C l \to 2 {C a C l}_{2} + H_{2} O + {C O}_{2}

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{C a C O}_{3} + 2 H C l \to {C a C l}_{2} + H_{2} O + 2 C O

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Solution

The correct option is A ${C a C O}_{3} + 2 H C l \to {C a C l}_{2} + H_{2} O + {C O}_{2}$
${C a C O}_{3} + H C l \to {C a C l}_{2} + H_{2} O + {C O}_{2}$

There is one Calcium atom on the left and one Calcium atom on the right so this is balanced.
There is 1 Carbon atom on the left and 1 Carbon atom on the right so this is balanced.
There are 3 Oxygen atoms on the left and 3 Oxygen atoms on the right so this is balanced.
There is 1 hydrogen atom on the left but 2 on the right so this is unbalanced. Therefore we need to balance it by using 2 molecules of HCl
${C a C O}_{3} + 2 H C l \to {C a C l}_{2} + H_{2} O + {C O}_{2}$

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Similar questions

C a C O_{3} + 2 H C l ⟶ C a C l_{2} + H_{2} O + C O_{2}

H C l

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C a C O_{3}

Calcium carbonate reacts with aqueous HCl to give CaCl₂and CO₂according to the reaction, CaCO₃+ 2HCl --> CaCl₂+ H₂O

What mass of CaCO3 is required to react completely with 25mL of 0.75 HCl?

C a C O_{3}

C O_{2}

C a C O_{3} + 2 H C l \to C a C l_{2} + H_{2} O + C O_{2}

C a C O_{3} = 100 u, H C l = 36.5 u C O_{2} = 44 u)

C a C O_{3} + 2 H C l \to C a C l_{2} + H_{2} O + C O_{2}

4.0

C a C O_{3}

C O_{2}

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