Give chemical equations for reaction of copper sulphate with excess of ${NH}_{4} OH$

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Solution

Chemical equations for the reaction of copper sulphate with an excess of ${NH}_{4} OH :$
When Copper sulphate $C u S O_{4}$ reacts with Ammonium hydroxide, $N H_{4} O H$ it first produces Ammonium sulphate ${(N H_{4})}_{2} S O_{4}$ and Copper hydroxide $C u {(O H)}_{2}$ precipitate.
$C u S O_{4} (s) + 2 N H_{4} O H (a q) \to {(N H_{4})}_{2} S O_{4} (s) + C u {(O H)}_{2} (s) + H_{2} O C o p p e r s u l p h a t e A m m o n i u m h y d r o x i d e \to Ammonium sulphate Copper Hydroxide$
Copper hydroxide of pale blue precipitate is formed that turns deep blue when excess ammonium hydroxide is added.
In the next step, ammonium sulphate, copper hydroxide further reacts with excess ammonium hydroxide to give a complex compound.
6242a76cf7d16 $(N H_{4})_{2} S O_{4} (s) + C u {(O H)}_{2} (s) + 2 N H_{4} O H (a q) \to [C u {(N H_{3})}_{4}] S O_{4} (s) + 4 H_{2} O (l) A m m o n i u m s u l p h a t e C o p p e r h y d r o x i d e E x c e s s A m m o n i u m h y d r o x i d e \to Tetrammine copper (II) suphate Water$
Thus the reaction of copper sulphate with ${NH}_{4} OH$ gives tetrammine copper(II) sulphate $[Cu {({NH}_{3})}_{4}] {SO}_{4}$ and water.

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