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Bijective Function

Given A={ x,y...

Question

Given $A = {x, y, z,} B = {u, v, w}, t h e f u n c t i o n f : A \to B d e f i n e d b y f (x) = u, f (y) = v, f (z) = w$ is

A

Surjective

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B

bijective

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C

injective

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D

all of the above

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Solution

The correct option is D
all of the above

$f = (x, u), (y, v), (z, w)$
clearly, f is one-one and onto

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Similar questions

Q. Let A = {a, b, c}, B = {u v, w} and let f and g be two functions from A to B and from B to A, respectively, defined as :

f = {(a, v), (b, u), (c, w)}, g = {(u, b), (v, a), (w, c)}.

Show that f and g both are bijections and find fog and gof.

A = x, y, z, B = u, v, w

f : A \to B

f (x) = u, f (y) = v, f (z) = w

A = x, y, z, B = u, v, w

f : A \to B

f (x) = u, f (y) = v, f (z) = w

A = x, y, z, B = u, v, w

f : A \to B

f (x) = u, f (y) = v, f (z) = w

A = {x, y, z}, B = {u, v, w}

. Then the function

f : A \to B

f (x) = u, f (y) = v, f (z) = w

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