Given a quadrilateral PQRS, which of the following statements is correct?

PQ + PS < QS

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PQ + QR > PR

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PS + SR + PQ < PR

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PQ + OR + RS < PR

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Solution

The correct option is A
PQ + PS < QS

Diagonal divides the quadrilateral into two triangles. And sum of two sides of a triangle is greater thn the third side.

Thus, PQ + QR > PR is the correct statement.

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The diagonal PR of a quadrilateral PQRS bisects the angles P and R, then

⎡ ⎢ ⎣ \begin{matrix} - q r & p (q + r) & p r + p q p q + q r & - p r & p q + q r q r + p r & q r + p r & - p q \end{matrix} ⎤ ⎥ ⎦

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(p q - q r + p r) (p q + q r) - (p r + p q) (p + q - r)

Construct a quadrilateral PQRS where PQ = 4 cm,QR = 6 cm, RS = 5 cm, PS = 5.5 cm and PR = 7 cm.[3 MARKS]

The area of quadrilateral PQRS, in which PQ = 7 cm, QR = 6 cm, RS = 12 cm, PS = 15 cm and PR = 9 cm:

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