Question

Given below is a parallelogram ABCD. Complete each statement along with the definition or property used.
(i) AD =
(ii) ∠DCB =
(iii) OC =
(iv) ∠DAB + ∠CDA =

Answer 1

The correct figure is

$$\begin{gathered} \left(\mathrm{i}\right) \\ \mathrm{AD}=\mathrm{BC}(\mathrm{opposite}\mathrm{sides}\mathrm{of}\mathrm{a}\mathrm{parallelogram}\mathrm{are}\mathrm{equal}) \\ \left(\mathrm{ii}\right) \\ \angle \mathrm{DCB}=\angle \mathrm{BAD}\left(\mathrm{opposite}\mathrm{angles}\mathrm{are}\mathrm{equal}\right) \\ \left(\mathrm{iii}\right) \\ \mathrm{OC}=\mathrm{OA}\left(\mathrm{diagonals}\mathrm{of}\mathrm{a}\mathrm{prallelogram}\mathrm{bisect}\mathrm{each}\mathrm{other}\right) \\ \left(\mathrm{iv}\right) \\ \angle \mathrm{DAB}+\angle \mathrm{CDA}=180°\left(\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{two}\mathrm{adjacent}\mathrm{angles}\mathrm{of}\mathrm{a}\mathrm{parallelogram}\mathrm{is}{180}^0\right) \end{gathered}$$