Given both vector A - B have the same magnitude of 1 unit- Find c- such that a-b-c-0 -3-1-2-3-1-2-B- 1-2-3-2-C- -3-2-1-2-D- -3-1-2-3-1-2-

The correct option is D Given magnitude of A amp; B are 1 Vector B = 1sin 30^∘î+1cos 30^∘ĵ = 1/2î+√(3)/2ĵ Vector A = 1cos 30^∘î+1sin 30^∘ĵ √(3)/2î+1/2ĵ ...

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Byju's Answer

Standard XII

Physics

Addition and Subtraction in Unit Vector Notation

Given both ve...

Question

Given both vector A & B have the same magnitude of 1 unit. Find $\to c$ such that $\to a + \to b + \to c = 0$ ?

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Solution

The correct option is A

Given magnitude of A & B are 1

Vector B = $- 1 s i n 30^{\circ}^i + 1 c o s 30^{\circ}^j$

= $- \frac{1}{2}^i + \frac{\sqrt{3}}{2}^j$

Vector A = $- 1 c o s 30^{\circ}^i + 1 s i n 30^{\circ}^j$

$- \frac{\sqrt{3}}{2}^i + \frac{1}{2}^j$

$\to A + \to B + \to C = 0$

$\Rightarrow \to C = - \to A - \to B$

= $- (\frac{- \sqrt{3}}{2}^i + \frac{1}{2}^j) - (- \frac{1}{2}^i + \frac{\sqrt{3}}{2}^j)$

= $(\frac{\sqrt{3}}{2} + \frac{1}{2})^i - (\frac{1}{2} + \frac{\sqrt{3}}{2})^j$

$\to C = (\frac{\sqrt{3} + 1}{2})^i - \frac{(\sqrt{3} + 1)}{2}^j$

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Given both vector A & B have the same magnitude of 1 unit. Find →c such that →a+→b+→c=0?

Given both vector A & B have the same magnitude of 1 unit. Find $\to c$ such that $\to a + \to b + \to c = 0$ ?