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Question

Given,

C(s)+O2(g)CO2(g);ΔH=395 kJ
S(s)+O2(g)SO2(g);ΔH=295 kJ
CS2(l)+3O2(g)CO2(g)+2SO2(g);ΔH=1110 kJ
The heat of formation of CS2(l) is:

A
250 kJ
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B
62.5 kJ
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C
31.25 kJ
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D
125 kJ
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Solution

The correct option is A 125 kJ
Since, the formation reaction of CS2 is,
C(s)+2S(s)CS2(l)
Since, the formation reaction of CS2 can also be derived using the given reaction as,
1streaction+2×2nd reaction3rd reaction
Hence, the enthalpy of the reaction,
[1streaction+2×2nd reaction3rd reaction] =ΔH1streaction+2×ΔH2nd reactionΔH3rd reaction =heat of formation of CS2(l)
Hence, ΔHf(CS2)=395+2×(295)(1110)=125kJ
Hence, the answer is option D.

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