The correct option is A Cu2+ ions can be reduced by H2(g)
Standard electrode potential is measured with reference to Standard Hydrogen electrode (SHE) which is taken as zero. Any electrode with positive standard potential can be reduced by H2.
As E0Cu2+/Cu=0.337>E0H+/H2
∴Cu2+ can be reduced by H2
E0(Sn2+/Sn)<0
So, it has a higher tendency to oxidise when coupled with H2(g)