Given figure shows measuring cylinder (in $c m^{3}$ ) before and after the immersion of an irregular solid object. The volume of the object is

c m^{3}

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c m^{3}

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c m^{3}

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c m^{3}

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Solution

The correct option is B 12 $c m^{3}$
Initial volume of water in the cylinder, $V_{1}$ = 70 $c m^{3}$
Final volume of water in the cylinder, $V_{2}$ = 82 $c m^{3}$
By bouncy law,
Hence volume of the object immersed in the cylinder = Final volume - initial volume = 82 $c m^{3}$ - 70 $c m^{3}$ = 12 $c m^{3}$

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Given figure shows measuring cylinder (in cm3) before and after the immersion of an irregular solid object. The volume of the object is

The correct option is B 12 cm3Initial volume of water in the cylinder, V1 = 70 cm3Final volume of water in the cylinder, V2 = 82 cm3By bouncy law, Hence volume of the object immersed in the cylinder = Final volume - initial volume = 82 cm3 - 70 cm3 = 12 cm3

Given figure shows measuring cylinder (in $c m^{3}$ ) before and after the immersion of an irregular solid object. The volume of the object is