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Question

Given n(A)=285, n(B)=195, n(U)=500, n(AB)=410, find n(AB).

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Solution

n(AB)=n(A)+n(B)n(AB)
n(AB)=285+195410=70

Similarly
n(AB)=n(A)+n(B)n(AB)
=n(U)n(A)+n(U)n(B)n(U \ (AB)
=500285+500195(500410)=430

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