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Standard XII

Mathematics

Pascal Triangle

Given positiv...

Question

Given positive integers r > 1, n > 2 and the coefficients of $(3 r)^{t h}$ and $(r + 2)^{t h}$ terms in the Binomial expansion of $(1 + x)^{2 n}$ are equal, then:

n = 2r

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n = 3r

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n = 2r+1

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None

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Solution

The correct option is A
n = 2r

$^{2 n} C_{3 r - 1} =^{2 n} C_{r + 1}$

3r-1+r+1=2n
n = 2r

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Given positive integers r > 1, n > 2 and the coefficients of (3r)th and (r+2)th terms in the Binomial expansion of (1+x)2n are equal, then:

The correct option is A n = 2r 2nC3r−1=2nCr+1 3r-1+r+1=2n n = 2r

Given positive integers r > 1, n > 2 and the coefficients of $(3 r)^{t h}$ and $(r + 2)^{t h}$ terms in the Binomial expansion of $(1 + x)^{2 n}$ are equal, then:

The correct option is A
n = 2r

$^{2 n} C_{3 r - 1} =^{2 n} C_{r + 1}$

3r-1+r+1=2n
n = 2r