Question

Given : $\sin A=\frac{3}{5},$ find :
(i) $\tan A$
(ii) $\cos A$

Answer 1

$sinA=3/5$

Let $CB=3$, $AC=5$

$\therefore$ $AB=x=4$

$tanA=\frac{CB}{AB}=\frac{3}{4}$

$cosA=\frac{AB}{AC}=\frac{4}{5}$