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Question

Given that E0Cu2+|Cu=0.34 V;E0Ag+|Ag=0.80 V:E0Mg3+|Mg=2.37 and E0Al3+|Al=1.66V
in which of the following cells the standard free energy decreases is maximum:

A
Mg|Mg2+(1M)||Cu2+(1M)|Cu
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B
Mg|Mg2+(1M)||Ag+(1M)|Ag
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C
Ag|Ag+(1M)||Al3+(1M)|Al
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D
Cu|Cu2+(1M)||Ag+(1M)|Ag
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Solution

The correct option is D Cu|Cu2+(1M)||Ag+(1M)|Ag
ΔG=nFE0
Where ΔG=Standard free energy
n=No. of electron
F=96500
ΔGCu=2×0.34×96500=65620
ΔGAg=1×0.80×96500=77200
ΔGMg=2×(2.37)×96500=457410
ΔGAl=3×(1.66)×96500=480570
We find that ΔG decreases is maximum in case of Cu and Ag.

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