Question

# Given that $$H.C.F.$$ of two numbers is $$23$$ and their $$L.C.M.$$ is $$1449$$. If one of the number is $$161$$, find the other number.

Solution

## Given, $$HCF = 23$$$$LCM = 1449$$Let the two numbers be $$a$$ and $$b$$. Let $$a = 161$$. We have to find $$b$$.We know that $$HCF(a,b) \times LCM(a,b) = a\times b$$$$\Rightarrow 23 \times 1449 = 161 \times b$$$$\Rightarrow 23\times \dfrac{1449}{161} = b$$$$\Rightarrow b = 23\times 9$$$$\therefore b = 207$$Thus, the other number is $$207$$.MathematicsRS AgarwalStandard X

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