Question

Given that $H.C.F.$ of two numbers is $23$ and their $L.C.M.$ is $1449$. If one of the number is $161$, find the other number.

Answer 1

Given, $HCF=23$

$LCM=1449$

Let the two numbers be $a$ and $b$. Let $a=161$. We have to find $b$.

We know that

$HCF(a,b)\times LCM(a,b)=a\times b$

$\Rightarrow 23\times 1449=161\times b$

$\Rightarrow 23\times \frac{1449}{161}=b$

$\Rightarrow b=23\times 9$

$\therefore b=207$

Thus, the other number is $207$.