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Question

Given that $$H.C.F.$$ of two numbers is $$23$$ and their $$L.C.M.$$ is $$1449$$. If one of the number is $$161$$, find the other number.


Solution

Given, $$HCF = 23$$

$$LCM = 1449$$

Let the two numbers be $$a$$ and $$b$$. Let $$a = 161$$. We have to find $$b$$.

We know that 

$$HCF(a,b) \times  LCM(a,b) = a\times b$$

$$\Rightarrow 23 \times  1449 = 161 \times  b$$

$$\Rightarrow 23\times \dfrac{1449}{161} = b$$

$$\Rightarrow b = 23\times 9$$

$$\therefore b = 207$$

Thus, the other number is $$207$$.

Mathematics
RS Agarwal
Standard X

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