Given that in a right angled triangle the length of two sides are 11 and 60. Find the perimeter of the triangle.

132

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145

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89

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200

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Solution

The correct option is A $132$
$\begin{matrix} 11^{2} + 60^{2} = 61^{2} \Rightarrow P e r i m e t e r o f Δ = 132 c m {∵ s i d e s 11, 60 & 61} \end{matrix}$

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