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Question

Given that Ka for HClO and HCN are 3.0×108 and 4.8×1010, respectively, the equilibrium constant for the reaction
HClO(aq)+CN(aq)ClO(aq)+HCN(aq), is:
  1. 1.6×1012
  2. 1.6×102
  3. 0.625×102
  4. 1.4×1017


Solution

The correct option is C 0.625×102
HClO(aq)+CNHCN+ClO
K=[HCN][ClO][HClO][CN]×[H+][H+]=[H+][ClO][HClO]×1{[H+][CN][HCN]}
=Ka(HClO)Ka(HCN)=3×1084.8×1010=0.625×102

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