Question

Given that $m=\frac{E_s}{E_t},I_t=$ Moment of inertia of timber portion and $I_s$ = Moment of inertial of a flitched beam made of steel and timber is given by

• A. $I_t+\frac{I_s}{m}$
• B. $I_s+\frac{I_t}{m}$
• C. $I_s+m{I}_t$
• D. $I_t+m{I}_s$

Answer 1

Answer: (B), (D)

$I_t+m{I}_s$

Transform from steel to timber
Then $I_t+m_s$
Transform from timber to steel

Then, $\frac{I_t}{m}+I_s$