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Heterogeneous Catalysis

Given that th...

Question

Given that the enthalpy of solution of the hydrated copper (II) sulphate is +11.3 kJ/mol, what is the enthalpy of hydration of the anhydrous solid.

97.321 kJ/mol

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87.321 kJ/mol

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77.971 kJ/mol

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Solution

The correct option is C 77.971 kJ/mol
$C u S O_{4} (s) + 5 H_{2} O (l) \to C u S O_{4} \cdot 5 H_{2} O (s) C u S O_{4} \cdot 5 H_{2} O (s) \to C u S O_{4} (l) + 5 H_{2} O (l) (1) △ H_{\circ} = 11.3 k j / m o l (g i v e n) C u S O_{4} (s) \to C u S O_{4} (l) q = m △ T = 50 \times 4.18 \times 8 = 1.672 k j m = \frac{4}{159.60} = 0.02506 (2) △ H_{\circ} = \frac{q}{m} = \frac{1.672}{0.02506} = 66.71 k j / m o l (2) + (1) C u S O_{4} \cdot 5 H_{2} O \to C u S O_{4} + 5 H_{2} O = 66.71 + 11.3 \approx 78 k j / m o l$

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= - 2

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N a C l (s)

- 790 k J . {m o l}^{- 1}

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N a C l (s)

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C u S O_{4} (s)

C u S O_{4} (s) + 5 H_{2} O ⟶ C u S O_{4} .5 H_{2} O

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m o l^{- 1}

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