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Question

Given that x = -9 is a root of āˆ£āˆ£ āˆ£āˆ£x372x276xāˆ£āˆ£ āˆ£āˆ£=0, the other two roots are . . . and . . . .

A
2
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B
8
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C
-5
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D
7
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Solution

The correct option is D 7
Given, ∣ ∣x372x276x∣ ∣=0
Applying R1R1+R2+R3
∣ ∣x+9x+9x+92x276x∣ ∣=0 (x+9)∣ ∣1112x276x∣ ∣=0
Applying C2C2C1 and C3C3C1
(x+9)∣ ∣1002x2071x7∣ ∣=0(x+9)(x2)(x7)=0
x =-9, 2, 7 are the roots.
Other two roots are 2 and 7.

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