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Question

Given that y=(cx+d)b;

then, what is the value of x, in ax+by+c=0

if b0 & (a+c)0,


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Solution

(Given: ~ax + by + c = 0,\)
Also given y=(cx+d)b, substitute this in ax+by+c=0
We get ax+[b(cx+d)b]+c=0
So, ax+cx+d+c=0
(a+c)x=dc
Therefore, x=(dc)(a+c). (1 mark)

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