Given that y - -cx - d-b-where b - 0- If-ax - by - c - 0 - where nbsp- nbsp- -a - c- - 0- then what is the value of x -d-c-a-c-d - c-a - c-a-c-d-c-d - c-a - c-

The correct option is B ( d c)/(a + c)Given ax + by + c = 0. Also given that nbsp; y=(cx+d)/b. Substituting this in ax + by + c = 0, we get ax + [b (cx + ...

Given that y ...

Question

Given that $y = \frac{(c x + d)}{b},where b \neq 0.$

$If a x + b y + c = 0, where (a + c) \neq 0$ ,
then what is the value of $x$ ?

\frac{(d + c)}{(a + c)}

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\frac{(- d - c)}{(a + c)}

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\frac{(a + c)}{(d + c)}

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\frac{(- d + c)}{(a + c)}

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Solution

The correct option is B $\frac{(- d - c)}{(a + c)}$
Given $a x + b y + c = 0.$
Also given that $y = \frac{(c x + d)}{b} .$
$Substituting this in a x + b y + c = 0,$
we get
$a x + [b \frac{(c x + d)}{b}] + c = 0.$

$S o, a x + c x + d + c = 0$
$\Rightarrow (a + c) x = - d - c$
$∴$ $x = \frac{(- d - c)}{(a + c)}$

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The correct option is B (−d−c)(a+c)Given ax+by+c=0. Also given that y=(cx+d)b. Substituting this in ax+by+c=0, we get ax+[b(cx+d)b]+c=0. So, ax+cx+d+c=0 ⇒(a+c)x=−d−c ∴ x=(−d−c)(a+c)

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