Given that y - cx - d - b -where b-0 - a - c -0then- what is the value of x- if a x-b y-c-0 -A- -d-c-a-c1-C- a-c-a-cD- None

The correct option is A ( d c)/(a + c) Given ax + by + c = 0, Also given y=(cx+d)/b, substitute this in ax + by + c = 0 We get ax + b[ (cx + d)/b] + c = 0 So ...

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Standard IX

Mathematics

Substitution Method

Given that y ...

Question

Given that $y = \frac{(c x + d)}{b}$ ;

where $b \neq 0 & (a + c) \neq 0$ ,

then, what is the value of x, if $a x + b y + c = 0$ ?

$\frac{(d + c)}{(a + c)}$

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$\frac{(- d - c)}{(a + c)}$

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$\frac{(a + c)}{(d + c)}$

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None

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Solution

The correct option is B
$\frac{(- d - c)}{(a + c)}$

Given $a x + b y + c = 0,$
Also given $y = \frac{(c x + d)}{b}$ , substitute this in $a x + b y + c = 0$
We get $a x + b [\frac{(c x + d)}{b}] + c = 0$
So $a x + c x + d + c = 0$
$(a + c) x = - d - c$
Therefore $x = \frac{(- d - c)}{(a + c)}$

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Similar questions

$G i v e n t h a t y = \frac{(c x + d)}{b}$ ;

then, what is the value of x, in $a x + b y + c = 0$

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Q. Given that,

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In the equation ax+by+c=0, if y= $\frac{(c x + d)}{b}$ then x =

In the equation $a x + b y + c = 0$ , if y= $\frac{(c x + d)}{b}$ and a = d, then what is the value of ' $x$ ' ?

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x

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Given that y=(cx+d)b; where b≠0 & (a+c)≠0, then, what is the value of x, if ax+by+c=0?

The correct option is B (−d−c)(a+c) Given ax+by+c=0, Also given y=(cx+d)b, substitute this in ax+by+c=0 We get ax+b[(cx+d)b]+c=0 So ax+cx+d+c=0 (a+c)x=−d−c Therefore x=(−d−c)(a+c)

Given that $y = \frac{(c x + d)}{b}$ ;

where $b \neq 0 & (a + c) \neq 0$ ,

then, what is the value of x, if $a x + b y + c = 0$ ?

The correct option is B
$\frac{(- d - c)}{(a + c)}$

Given $a x + b y + c = 0,$
Also given $y = \frac{(c x + d)}{b}$ , substitute this in $a x + b y + c = 0$
We get $a x + b [\frac{(c x + d)}{b}] + c = 0$
So $a x + c x + d + c = 0$
$(a + c) x = - d - c$
Therefore $x = \frac{(- d - c)}{(a + c)}$