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Question

Given the angles of a triangle are in A.P with a common difference equal to the smallest angle. Find the value of cosA X cosB X cosC, where A, B and C are the angles of the triangle.



A

0

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B

(1/2)

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C


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D


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Solution

The correct option is A

0


Let A be the smallest angle,

The other angles will be 2A, 3A.

Sum of angles in a triangle =180

A+2A+3A=180

A=30

The other two angles will be 60 and 90

cos90=0

So, cosA X cosB X cosC = 0.


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