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Question

Given the area of rectangle is A=25a235a+69. The length is given as (5a3).Find the width of the rectangle.


  1. 5a3

  2. 5a4

  3. 4a5

  4. a4


Solution

The correct option is B

5a4


Let y be the width.
Given: Area =25a235a+69

We know that, area of a rectangle = Length ×breadth

Hence, y×(5a3)=25a235a+69
y=(25a235a+69)÷(5a3)
By long division method, 

5a35a23)¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯25a235a+69            25a212a                 +           ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯                                           23a+69                      23a+69                      +                    ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯                                                  0
y=5a23Width of the rectangle =5a23

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