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Question

Given the parabola y2=4ax, find the pair of tangents from the point (2, 6) where a =2.


A
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B

36x2 - 4y2 - 8xy + 64x + 64y + 64 =0

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C

36x2 - 4y2 - 48xy + 64x + 64y + 64 =0

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D

36x2 - 64y2 - 48xy + 64x + 64y + 64 =0

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Solution

The correct option is C

36x2 - 4y2 - 48xy + 64x + 64y + 64 =0


It is useful to rememberthe formula for pair of tangents from a point to a parabola which is T2 = ss

Where, T = yy 2a (x + x)

S = y2 4ax

S = y2 4ax

Here, x = 2, y = 6, a=2

T2 = ss (y(6) 2 (2) (x+2))2 = y2 4ax (62 4(2)(2))

36x2 4y2 48xy + 64x + 64y + 64 =0


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