Question

# Given the speed-time graph of a golf ball shot from ground at t = 0. What will be the time of flight?

A

1s

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B

0.8s

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C

0.6s

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D

1.2s

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Solution

## The correct option is B 0.8s at t = 0, speed is 5 ms, this means, u = 5 ms. Also minimum speed is 3 ms. For a projectile speed is minimum and equal to its horizontal component at the highest point of its trajectory, as the vertical component is zero at this point. Let θ be the angle of projection, then, u cos θ = 3 ⇒ 5 cos θ = 3 ⇒ cos θ = 35 θ = 53∘ ∴ Time of flight = 2usinθg = 2×5×sin53∘10 2×5×45× 110 ⇒ 45s = 0.8s

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