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Question

Given two independent events A and B such that P(A)=0.3,P(B)=0.6. Find
(i) P(AandB)
(ii) P(AandnotB)
(iii) P(AorB)
(iv) P(neitherAnorB)
If the sum of the above probablities is m enter 100m

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Solution

It is given that P(A)=0.3 and P(B)=0.6
Also, A and B are independent events.
(i) P(AandB)=P(A)P(B)
P(AB)=0.3×0.6=0.18
(ii) P(AandnotB)=P(AB)
=P(A)P(AB)
=0.30.18
=0.12
(iii) P(AorB)=P(AB)
=P(A)+P(B)P(AB)
=0.3+0.60.18
=0.72
(iv) P(neitherAnorB)=P(AB)
=P((AB))
=1P(AB)
=10.72
=0.28

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