Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell?

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Solution

For a face-centred unit cell:

It is given that the atomic radius, r = 0.144 nm

So,

= 0.407 nm

Hence, length of a side of the cell = 0.407 nm

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Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell?

For a face-centred unit cell: It is given that the atomic radius, r = 0.144 nm So, = 0.407 nm Hence, length of a side of the cell = 0.407 nm

For a face-centred unit cell:

It is given that the atomic radius, r = 0.144 nm

So,

= 0.407 nm

Hence, length of a side of the cell = 0.407 nm