The correct option is B FeSO_4. 7H_2 O Green vitriol is #160; FeSO_4. 7H_2 O .Hence, Option #34;B #34; is the correct answer. ...

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Green vitriol...

Question

Green vitriol is

C u S O_{4} . 5 H_{2} O

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F e S O_{4} . 7 H_{2} O

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C a S O_{4} . 2 H_{2} O

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Z n S O_{4} . 7 H_{2} O

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Solution

The correct option is B $F e S O_{4} . 7 H_{2} O$
Green vitriol is $F e S O_{4} . 7 H_{2} O$ .
Hence, Option "B" is the correct answer.

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Similar questions

M n S O_{4} .4 H_{2} O

F e S O_{4} .7 H_{2} O

N i S O_{4} .6 H_{2} O

C u S O_{4} .5 H_{2} O

(F e S O_{4} .7 H_{2} O, C u S O_{4} .5 H_{2} O, M n S O_{4} .4 H_{2} O, Z n S O_{4} .7 H_{2} O)

1.39

(F e S O_{4} . 7 H_{2} O)

F e S O_{4}

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F e S O_{4} .7 H_{2} O, Z n S O_{4} .7 H_{2} O

C u S O_{4}, F e C l_{3}, F e C l_{2}

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