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H2+Cl22HCl;  ΔH=44 kcal
Heat of formation of HCl is:
  1. +44 kcal
  2. -44 kcal
  3. +22 kcal
  4. -22 kcal


Solution

The correct option is D -22 kcal
Given reaction is,
H2+Cl22HCl    ΔH=44 kcal
Heat of formation is the enthalpy change accompanying the formation of one mole of the compound from its constituent elements.
For 2 moles of HCl,ΔH=44 kcal
For 1 mole of HCl, ΔH=442=22 kcal

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