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Question

H2+Cl22HCl;ΔH=44kcal

2Na(s)+2HCl(g)2NaCl(s)+H2(g);ΔH=152kcal

For the reaction 2Na+Cl22NaCl;ΔH=?


A
-108 kcal
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B
-196 kcal
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C
-98 kcal
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D
54 kcal
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Solution

The correct option is C -196 kcal
(i) H2+Cl22HCl;ΔH=44kcal
(ii) 2Na(s)+2HCl(g)2NaCl(s)+H2(g);ΔH=152kcal
For the reaction 2Na+Cl22NaCl, add eq (i) and (ii) , we get
ΔH=44+(152)=196kcal
Hence option (B) is correct.

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