Question

$H_{2}S{O}_5+H_{2}O\to H_{2}S{O}_4+H_2{O}_2$
Oxidation number of sulphur in $H_{2}S{O}_5$ in the above reaction is :

• A. $6$
• B. $4$
• C. $5$
• D. $2$

Answer 1

The correct option is A $6$

Formation of $H_2{O}_2$ indicates that there is one peroxy linkage in $H_{2}S{O}_5$. The oxidation state of H = $+1$.
Therefore, $x+2-2-6=0$ or, $x=+6$
Hence, $x=6$.
Thus, oxidation number of sulphur = $+6$.
The structure is given below: