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Byju's Answer
Standard XII
Chemistry
Reduction of Carboxylic Acids
CH 3 COCl X⟶ ...
Question
A
H
2
/ Pt
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B
H
2
/ Pd - BaSO
4
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C
Cr
2
O
7
-2
/ H
+
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D
Zn - Hg / HCl
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Solution
The correct option is
B
H
2
/ Pd - BaSO
4
Formation of Y is Rosenmund's reduction
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Similar questions
Q.
C
6
H
5
C
O
N
H
C
H
3
can be converted into
C
6
H
5
C
H
2
N
H
C
H
3
by
Q.
H
3
C
−
C
O
C
l
H
2
/
P
d
−
B
a
S
O
4
−
−−−−−−−−
→
A
Z
n
−
H
g
/
H
C
l
−
−−−−−−−
→
B
What are A and B?
Q.
A) Grignard reagent
1)
H
2
/
P
d
−
B
a
S
O
4
B) Clemmensen reduction
2)
N
2
H
4
/
K
O
H
/
C
H
2
O
H
−
C
H
2
O
H
C) Rosenmunds reduction
3)
C
H
3
M
g
X
D) Wolf-Kishner reduction
4)
Z
n
−
H
g
/
C
o
n
c
.
H
C
l
5)
H
2
/
N
i
Q.
Which of the comparison regarding
Z
n
,
C
d
,
H
g
is/are correct?
(I)
Z
n
C
l
2
is ionic whereas
C
d
C
l
2
and
H
g
C
l
2
are covalent.
(II)
Z
n
and
C
d
dissolves in dilute acid
(
H
C
l
)
liberating
H
2
whereas
H
g
do not.
(III)
Z
n
and
C
d
forms precipitate of
Z
n
(
O
H
)
2
and
C
d
(
O
H
)
2
but
H
g
forms coloured precipitate of
H
g
(
O
H
)
2
.
(IV) All forms
A
2
+
2
type ion.
Q.
For,
Z
n
(
s
)
+
2
H
C
l
(
a
q
)
⇌
Z
n
C
l
2
(
a
q
)
+
H
2
(
g
)
what will be the expression of
K
c
:
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