$H C l$ gas is passed into water yielding a solution of density $1.095$ g/mL and containing $30$ $H C l$ by weight. Calculate the molarity of the solution;

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Solution

$H C l$ gas on passing into water yields a solution of density $1.095$ g/mL and containing $30 %$ $H C l$ by weight.
The expression for the molarity of solution is, $M = \frac{percentage by weight \times 10 \times d}{M w_{2}}$ .
Substituting values in the above expression, we get,
$M = \frac{30 \times 10 \times 1.095}{36.5} = 9 M$
Hence, the molarity of the solution is $9 M$ .

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HCl gas is passed into water yielding a solution of density 1.095 g/mL and containing 30 HCl by weight. Calculate the molarity of the solution;

$H C l$ gas is passed into water yielding a solution of density $1.095$ g/mL and containing $30$ $H C l$ by weight. Calculate the molarity of the solution;