Question

Heat energy absorbed by a system in going through a cycle process is shown in the figure [$V$ in $litres$ and $P$ in $KPa$] is

• A. ${10}^7\pi J$
• B. ${10}^4\pi J$
• C. ${10}^2\pi J$
• D. ${10}^3\pi J$

Answer 1

Answer: (C)

${10}^2\pi J$

Work done = Area within loop.
Area of an ellipse $=\frac{\pi }{4}a\times b$
Area of an ellipse $=\frac{\pi }{4}(20\ast {10}^{-3})(20\ast {10}^3)J={10}^2\pi J$
Work done in loop $={10}^2\pi J$
Hence option C is correct.