wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Heat of 20 Kcal is supplied to the system and 8400 J of external work is done on the system so that its volume decreases at constant pressure. The change in internal energy is (J=4200 J/kcal)

A
9.24×104 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
7.56×104 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8.4×104 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10.5×104 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 9.24×104 J
ΔQ=20×103cal
=20×4200J
=84×103J
ΔW=8400J
ΔV=ΔQΔW
=84000+8400
=92400
=9.24×104
Hence,
option (A) is correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thermochemistry
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon