Heat of neutralisation for the given reaction NaOH+HCl→NaCl+H2O is 57.9 kJ/mole. What will be the heat released when 0.75 moles of NaOH is titrated against 1.25 moles of HCl?
The correct option is B 43.42 kJ
Heat of neutralization for 1 mole of HCl and NaOH is 57.9 kJ/mole.
Here, NaOH is the limiting reagent and decides the extent of reaction.
So, heat of neutralization for 0.75 mole of reactant NaOH is 0.75 mol×57.9 kJ/mole = 43.42 kJ