Heat required to convert one gram of ice at 0- C into steam at 100- C is given L steam -536 cal - gm A- 0-01 kilocalorieB- 716 calorieC- 1 kilocalorieD- 100 calorie

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Heat required...

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Heat required to convert one gram of ice at $0^{o} C$ into steam at $100^{o} C$ is (given $L_{s t e a m}$ = 536 cal/gm)

100 calorie

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0.01 kilocalorie

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716 calorie

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1 kilocalorie

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Heat required to convert one gram of ice at $0^{\circ} C$ into steam at $100^{\circ} C$ is (given $L_{s t r e a m}$ = 536 cal/gm)

0^{_{-}^{0}} C

100^{_{-}^{0}} C

L_{s t e a m}

Heat required to convert one gram of ice at $0^{\circ} C$ into steam at $100^{\circ} C$ is (given $L_{s t r e a m}$ = 536 cal/gm)

1 g

0^{0} C

100^{0} C

L_{s t e a m} = 536 c a l / g

10^{0} C

100^{0} C

536 c a l / g m - K

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