Question

# Henry's law constant for the molality of methane in benzene at $$298\ K$$ is $$4.27 \times 105\ mm\ Hg$$. Calculate the solubility of methane in benzene at $$298\ K$$ under $$760\ mm\ Hg$$.

Solution

## It is given that the molality of methane in benzene at $$298\ K$$ is $$4.27\times 10^5$$ mm of Hg.$$\displaystyle C = \dfrac {p}{k}$$$$\displaystyle C = \dfrac {760 \: mm \: Hg}{4.27 \times 10^5 \: mm \: Hg / m}$$$$\displaystyle C = 1.78 \times 10^{-3}$$  mHere, C is the molality of methane in benzene, p is the pressure of methane and k is Henry's law constant.ChemistryNCERTStandard XII

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