Question

Highest oxidation State of manganese in fluorides is +4 $\left(Mn{F}_4\right)$ but highest oxidation state in oxides is +7 $\left(M{n}_2{O}_7\right)$ because:

• A. fluorine is more electronegative than oxygen
• B. fluorine does not possess d-orbitals
• C. fluorine stabilises lower oxidation state
• D. in covalent compounds, fluorine can form single bond only while oxygen forms double bond

Answer 1

The correct option is D in covalent compounds, fluorine can form single bond only while oxygen forms double bond

Higher oxidation state is related to the number of bond formation in the compound.Since Fluorine$\left(F\right)$ can form only single bonds while Oxygen$\left(O\right)$ forms double bond.