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B
m - bromoaniline
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C
bromobenzene
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D
m - bromoethyl benzene
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Solution
The correct option is C m - bromoaniline The Hoffmann's bromomide reaction is as follows : RCONH2+Br2+KOH→RNH2 Here, the R group is m-bromobenzene group So, m-bromoaniline is the product.