CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Holding on to a towrope moving parallel to a frictionless ski slope, a 50kg skier is pulled up the slope, which is at an angle of 8.0o with the horizontal.What is the magnitude of the force on the skier from the rope when (a) the magnitude of the skier’s velocity is constant at 2.0m/s and (b) v = 2.0m/s as v increases at a rate of 0.10m/s2?

Open in App
Solution

(a) Constant velocity implies zero acceleration, so the “uphill” force must equal (in magnitude) the “downhill” force: T=mgsinθ. Thus, with m=50kg and θ=8.0o , the tension in the rope equals 68N.
(b) With an uphill acceleration of 0.10m/s2, Newton’s second law (applied to the x axis) yields
Tmgsinθ=maT(50kg)(9.8m/s2)sin8.0o=(50kg)(0.10m/s2)
which leads to T=73N.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon