How are the two atoms $_{92}^{235} P$ and $_{92}^{238} P$ similar?
(i) They have the same number of protons
(ii) They have the same number of neutrons
(iii) They have the same number of electrons

Only (i)

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Only (i) and (ii)

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Only (i) and (iii)

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(i), (ii) and (iii)

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Solution

The correct option is D Only (i) and (iii)
$_{Z}^{A} X$ : Ideal element representation

Here, $Z =$ atomic number $=$ number of protons

$A$ $=$ mass number $=$ number of protons $+$ number of neutrons

Also, the number of protons $=$ number of electrons

So, for $_{92}^{235} P$ and $_{92}^{238} P$ :

$_{92}^{235} P$ : number of protons $=$ $92$ $=$ $Z$

Number of electrons $=$ $92$ $=$ number of protons

Number of neutrons $=$ $A - Z$ $=$ $235 - 92$ $=$ $143$

$_{92}^{238} P$ : number of protons $=$ $Z$ $=$ $92$

Number of electrons $=$ number of protons $=$ $Z$ $=$ $92$

Number of neutrons $=$ $238 - 92$ $=$ $146$

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How are the two atoms 23592P and 23892P similar?(i) They have the same number of protons(ii) They have the same number of neutrons(iii) They have the same number of electrons

How are the two atoms $_{92}^{235} P$ and $_{92}^{238} P$ similar?
(i) They have the same number of protons
(ii) They have the same number of neutrons
(iii) They have the same number of electrons