How do you account for the reducing behaviour of $H_{3} P O_{2}$ on the basis of its structure ?

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Solution

In $H_{3} P O_{2}$ . two H atoms are bonded directly to P atom which imparts reducing character to the acid.

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How do you account for the reducing behaviour of H3PO2 on the basis of its structure ?

In H3PO2. two H atoms are bonded directly to P atom which imparts reducing character to the acid.

How do you account for the reducing behaviour of $H_{3} P O_{2}$ on the basis of its structure ?

In $H_{3} P O_{2}$ . two H atoms are bonded directly to P atom which imparts reducing character to the acid.