CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

How do you calculate the relative formula mass $$(M)$$ of calcium carbonate? Relative atomic masses $$C = 12, O = 16, Ca = 40$$?


Solution

An ionic compound formed between calcium ion $$(Ca^{2+})$$ and carbonate ion $$(CO_{3}^{2-})$$.

After crossing over the number of the charges in $$Ca^{2+}$$ and carbonate ion $$CO_{3}^{2-}$$ we'll get $$Ca_2(CO_3)_2$$, which can be further simplified into  $$CaCO_3$$.

And then, we multiply with its atomic mass and add them all up, like this,

Relative formula mass $$CaCO_3 = (1 \times 40) + (1 \times 12) + (3 \times 16) = 100$$

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image