Question

# How do you calculate the relative formula mass $$(M)$$ of calcium carbonate? Relative atomic masses $$C = 12, O = 16, Ca = 40$$?

Solution

## An ionic compound formed between calcium ion $$(Ca^{2+})$$ and carbonate ion $$(CO_{3}^{2-})$$.After crossing over the number of the charges in $$Ca^{2+}$$ and carbonate ion $$CO_{3}^{2-}$$ we'll get $$Ca_2(CO_3)_2$$, which can be further simplified into  $$CaCO_3$$.And then, we multiply with its atomic mass and add them all up, like this,Relative formula mass $$CaCO_3 = (1 \times 40) + (1 \times 12) + (3 \times 16) = 100$$Chemistry

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