How long after the beginning of motion is the displacement of a harmonically oscillating particle equal to one half its amplitude if the period is 24s and particle starts from rest
A
12s
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B
2s
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C
4s
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D
6s
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Solution
The correct option is C4s Let's draw the phasor diagram
cosθ=A2A=12θ60°
On rotation of 960° it takes 24 sec the for 60° rotation it will take 246=4sec