Question

How many $3$ -digit even numbers can be formed from the digit $1,2,3,4,5,6$ if digits can be repeated ?

Answer 1

To be a even number the number should end with either $2,4$ or $6$.

Possibilities at unit’s place $=3$

So, ten’s place can have $6$ numbers.

Possibilities at ten’s place $=6$

Therefore, at the hundred’s place there can be $6$ of the $6$ numbers.

Possibilities at hundred’s place $=6$.

Total number of possibilities$=3\times 6\times 6=108$ ways