Question

How many 3 - digit numbers can be formed using the digits 1, 2, 3, 4, 5, 6 without repeating any digit.

Answer 1

$3$ Digit number

No repetition

$1,2,3,4,5,6$

Number of possible numbers

${\Rightarrow }^6{P}_3\Rightarrow 6\times 5\times 4\Rightarrow 120$

Therefore $120$ such numbers are possible